## Time & Distance Solved Questions For IBPS, SBI and Other Bank Exams - Page 3

Time & Distance Solved Questions (Page 3 of 3)

**Question 1**

A man covers X km in t hours at S km/hr; another man covers X/2 km in 2t hours at R km/hr. Then the ratio S:R equals

a) 4:1 b) 2:1 c) 1:4 d) 1:2

**Answer : **a) 4:1

Solution :

Distance covered by 1st man at S km/hr = X km

Time taken by him = t hours.

Therefore, Speed = S = X/t km/hr.

Distance covered by 2nd man at R km/hr = X/2 km

Time taken by him = 2t hours.

Therefore, Speed = R = (X/2)/2t km/hr = X/4t km/hr.

Required ratio = S:R = X/t : X/4t = 1 : 1/4 = 4:1.

**Question 2**

If a cyclist starts at 7 km/hr and he increases his speed in every 3 hours by 1 km/hr then the time taken by the cyclist to cover 113 km is:

a) 27/2 hours b) 20/3 hours c) 12 hours d) 13 hours

**Answer : **d) 13 hours

Solution :

Initial speed of the cyclist = 7km/hr.

Distance covered in 1st 3 hours = 7 x 3 = 21 km.

After increasing, 1km/hr for every 3 hours period,

Distance covered in 2nd 3 hours period = 8 x 3 = 24 km.

Distance covered in 3rd 3 hours period = 9 x 3 = 27 km.

Distance covered in 4th 3 hours period = 10 x 3 = 30 km.

Total distance covered = 21 + 24 + 27 + 30 = 102 km.

Remaining km to cover = 113 - 102 = 11 km.

Speed in 5th 3 hours period = 11 km/hr.

Time to cover 13 km at 11km/hr = 11/11 hours = 1 hour.

Now, the total time taken by him for 113 km = (3 + 3 + 3 + 3 + 1) = 13 hours.

**Question 3**

A bike rider starts at 60 km/hr and he increases his speed in every 2 hours by 3 km/hr. Then the maximum distance covered by him in 24 hours is:

a) 1000km b) 918km c) 899 km d) none of these

**Answer : **b) 918 km.

Solution :

Speed of the rider = 60km/hr.

Distance covered in 1st 2 hours = 60 km.

He increased his speed in every 2 hours by 3 km/hr.

Distance covered in every 2 hours will be, 60, 63, 66,... upto 12 terms.(for 24 hours).

The above series is an A.P series;

Sum of first n terms = (n/2)(2a+(n-1)d)

Here, a = 60, d = 3 and n = 12.

Sum of first 12 terms = (12/2)(2(60)+(11)3) = 6(120 + 33) = 6(153) = 918.

Hence, he covers 918 km in 24 hours.

**Question 4**

A car starts at 10 am with a speed of 50 km/hr. Due to the problem in engine it reduces its speed as 10 km/hr for every 2 hours. After 11 am, the time taken to covers 10 km is:

a) 12 minutes and 10 seconds

b) 15 minutes and 09 seconds

c) 13 minutes and 20 seconds

d) none of these

**Answer : **c) 13 minutes and 20 seconds

Solution :

Initial speed of the car = 50km/hr

Due to engine problem, speed is reduced to 10km for every 2 hours(i.e., 5 km per hour).

Speed of the car at 11 am = (50 - 5) = 45km/hr

Time to cover 10 km at 45 km/hr = distance/speed = 10/45 hours. = 2/9 hours

= 2/9 x 60 minutes = 40/3 minutes = 13 minutes + 1/3 minutes

= 13 minutes + 1/3 x 60 seconds

= 13 minutes and 20 seconds.

Time & Distance Solved Questions (Page 3 of 3)