## Probability Solved Questions For IBPS, SBI and Other Bank Exams - Page 2

**Question 1**

Two dice are thrown simultaneously. What is the probability of getting the sum of the face number is odd?

a) 1/3 b) 2/3 c) 1/2 d) 3/4

**Answer:**c) 1/2

Solution:

In a simultaneous throw of two dice, we have n(s) = 6 x 6 = 36

Let E = event of getting two numbers whose sum is odd.

Then E = { (1,2), (1,4), (1,6), (2,1), (2,3), (2,5), (3,2), (3,4), (3,6), (4,1), (4,3), (4,5), (5,2), (5,4), (5,6), (6,1), (6,3), (6,5)}

therefore, n(E) = 18

And P(E) = p( getting two numbers whose sum is odd)

P(E) = n(E)/n(s) = 18/36 = 1/2

Hence the answer is 1/2

**Question 2**

Two dice are thrown simultaneously. What is the probability of getting the sum of the face number is at least 10?

a) 1/6 b) 1/3 c) 2/3 d) 5/6

**Answer:**a) 1/6

Solution:

In a simultaneous throw of two dice, we have n(s) = 6 x 6 = 36

Let E = event of getting two number whose sum is at least 10.

Then E = { (4,6), (5,5), (5,6), (6,4), (6,5), (6,6) }

therefore, n(E) = 6

And P(E) = p( getting two numbers whose sum is at least 10)

P(E) = n(E)/n(s) = 6/36 = 1/6

Hence the answer is 1/6

**Question 3**

Two dice are thrown simultaneously. What is the probability of getting the sum of the face number is at most 5?

a) 2/18 b) 5/18 c) 4/9 d) 2/9

**Answer:**b) 5/18

Solution:

In a simultaneous throw of two dice, we have n(s) = 6 x 6 = 36

Let E = event of getting two numberswhose sum is at most 5.

Then E = { (1,1), (1,2), (1,3), (1,4), (2,1), (2,2), (2,3), (3,1), (3,2), (4,1)}

therefore, n(E) = 10

And P(E) = p( getting two numbers whose sum is at most 5)

P(E) = n(E)/n(s) = 10/36 = 5/18

Hence the answer is 5/18

**Question 4**

Two dice are thrown simultaneously. What is the probability of getting the face numbers are same?

a) 1/6 b) 2/3 c) 4/9 d) 5/6

**Answer:**a)1/6

Solution:

In a simultaneous throw of two dice, we have n(s) = 6x6 = 36

Let E = event of getting two numbers are same.

Then E = { (1,1), (2,2), (3,3), (4,4), (5,5), (6,6)}

therefore, n(E) = 6

And P(E) = p( getting two numbers are same)

P(E) = n(E)/n(s) = 6/36 = 1/6

Hence the answer is 1/6