Percentage Solved Questions For IBPS, SBI and Other Bank Exams - Page 1

You will find 31 problems in 8 pages..

Percentage Problems Solved Questions (Page 1 of 8)

Dear Reader,

Below you will find important formulas of percentage problems. Following that you will find solved questions. These questions will help you in preparation for all bank exams including IBPS, SBI, RRB and other banks.

Percent: By a certain percent we mean that many hundredths.

Thus, X percent means X hundredths, written as X%.

To express X% as a fraction: We have, X% = X / 100

Ex: 15% = = 3 / 20

To express a / b as a percent: We have, a / b = (a / b x 100)%

Ex: 6 / 5 = (6 / 5 x 100)% = 120%

Question 1
If the numerator of a fraction is increased by 150% and the denominator of the fraction is increased by 350%, the resultant fraction is 25/51 . What is the original fraction?

1) 11/17 2) 11/15 3) 15/17 4) 13/15 5) None of these

Answer :15/17

Solution :

let the original fraction be x/y
let us assume that the value of x is 100 and the value of y is 100
then the numerator of the resultant fraction is 250% of x, that is 100+(150/100)*100
similarly the denominator of the resultant fraction is 450%
given that, (250% of x)/(450% of y)=25/51
then (x/y) =(25/51)*(450/250)
hence x/y = 15/17


Question 2

if the numerator of a fraction is increased by 180% and the denominator of the fraction is increased by 450% then the new fraction will be 35/22. find the real fraction.

(1)25/8 (2)15/11 (3)25/11 (4)8/15

Answer :25/8

Solution :

let the original fraction be x/y
then (280% of x)/(550% of y) =35/22
x/y =(35/22)*(550/280) = 25/8


Question 3

if the denominator of a fraction is decreased by 25% and the numerator is increased by 85%, the resultant fraction will be 74/28. find the original fraction.

1)31/13 2)13/31 3)15/14 4)14/13

Answer :15/14

Solution :

let the original fraction be x/y
then (185% of x)/(75% of y) = 74/28
x/y = (74/28)*(75/185)
=15/14


Question 4

if the numerator and denominator of a fraction is diminished and increased by 70% respectively then the resultant fraction is 39/34. find the original fraction.

1)17/11 2)13/11 3)13/2 4)17/2

Answer :13/2

Solution :

let the original fraction be x/y
then (30% of x)/(170% of y) = 39/34
x/y = (39/34)*(170/30)
= 13/2


Percentage Problems Solved Questions (Page 1 of 8)

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