## Mixture & Alligation Solved Questions For IBPS, SBI and Other Bank Exams - Page 1

Mixture & Alligation Solved Questions (Page 1 of 2)

Dear Reader,

Below you will find important formulas of mixture & alligation problems. Following that you will find solved questions. These questions will help you in preparation for all bank exams including IBPS, SBI, RRB and other banks.

**Question 1**

A fruit seller mix two qualities of fruits costing Rs.75 and Rs.50 per kg respectively. In what ratio he should mix the mixture to get worth Rs.65 per kg ?

a) 1:3 b) 1:2 c) 2:3 d) 3:2

**Answer:** c)2:3

Solution:

Cost of 1 kg fruit of 1st quality = Rs.75

cost of 1 kg fruit of 2nd quality = Rs.50

i.e.,

C.P. of dearer (d) = Rs.75

C.P. of cheaper(c) = Rs.50

And Mean price (m) = Rs.65

d - m = 75 - 65 = 10

And m - d = 65 - 50 = 15

Required rate = Quantity of cheaper / Quantity of dearer = d - m / m - c = 10/15 = 2/3

Hence the answer is 2:3

**Question 2**

Find the ratio in which milk at Rs.12.50 per litre be mixed with milk at Rs.10.70 per litre to make a mixture worth Rs.11.50 per litre.

a)5:4 b)2:3 c)1:5 d)2:5

**Answer:** a)5:4

Solution:

Cost of 1 litre milk of 1st type = Rs.12.50 = 1250 paise and

Cost of 1 litre milk of 2nd type = Rs.10.70 = 1070 paise

i.e,

C.P. of dearer (d) = 1250 p

C.P. of cheaper(c) = 1070 p

And Mean price (m) = 1150 p

Then, d - m = 1250 p - 1150 p = 100 p

and m - c = 1150 p - 1070 p = 80 p

Required rate = Quantity of cheaper / Quantity of dearer = d - m / m - c = 100/80 = 5:4

Hence the answer 5:4

**Question 3**

In what ratio should a seller mix oil of Rs.62 per litre with oil at Rs.72 per litre, so that the mixture would worth Rs.64.50 per litre?

a) 2:3 b) 1:3 c) 4:3 d) 3:1

**Answer:** d)3:1

Solution:

Cost of 1 litre oil of 1st type = Rs.62

Cost of 1 litre oil of 2nd type = Rs.72

Mean price (m) = Rs.64.50

i.e.,

C.P. of dearer (d) = Rs.72

C.P. of cheaper(c) = Rs.62

Then d - m = 7.50

and, m - c = 2.50

Now, the required rate = Quantity of cheaper / Quantity of dearer = d - m / m - c = 7.5 : 2.5 = 3:1

Hence the answer is 3:1

**Question 4**

The milk seller adds water to milk worth Rs.11 per litre. In what ratio should he mix to get a mixture of cost of Rs.9.90 per litre ?

a)1:3 b) 1:9 c) 2:5 d) 1:11

**Answer:** b)1:9

Solution:

Cost of 1 litre water = Rs.0

Cost of 1 litre milk = Rs.11

Mean price(m) = Rs.9.90

C.p of dearer = Rs.11

C.P of cheaper = Rs.0

Then d - m = 11 - 9.90 = Rs.1.10

And, m - c = Rs.9.90

Now, the required rate = Quantity of cheaper / Quantity of dearer = d - m / m - c = 1.1 : 9.9

= 11:99 = 1:9

Hence the answer is 1:9

Mixture & Alligation Solved Questions (Page 1 of 2)