Probability Solved Questions For IBPS, SBI and Other Bank Exams - Page 2

You will find 14 problems in 4 pages..

Probability Problems Solved Questions (Page 2 of 4)

Question 1

Two dice are thrown simultaneously. What is the probability of getting the sum of the face number is odd?
a) 1/3 b) 2/3 c) 1/2 d) 3/4

Answer:c) 1/2

Solution:

In a simultaneous throw of two dice, we have n(s) = 6 x 6 = 36
Let E = event of getting two numbers whose sum is odd.
Then E = { (1,2), (1,4), (1,6), (2,1), (2,3), (2,5), (3,2), (3,4), (3,6), (4,1), (4,3), (4,5), (5,2), (5,4), (5,6), (6,1), (6,3), (6,5)}
therefore, n(E) = 18
And P(E) = p( getting two numbers whose sum is odd)
P(E) = n(E)/n(s) = 18/36 = 1/2

Hence the answer is 1/2


Question 2

Two dice are thrown simultaneously. What is the probability of getting the sum of the face number is at least 10?
a) 1/6 b) 1/3 c) 2/3 d) 5/6

Answer:a) 1/6

Solution:

In a simultaneous throw of two dice, we have n(s) = 6 x 6 = 36
Let E = event of getting two number whose sum is at least 10.
Then E = { (4,6), (5,5), (5,6), (6,4), (6,5), (6,6) }
therefore, n(E) = 6
And P(E) = p( getting two numbers whose sum is at least 10)
P(E) = n(E)/n(s) = 6/36 = 1/6

Hence the answer is 1/6


Question 3
Two dice are thrown simultaneously. What is the probability of getting the sum of the face number is at most 5?
a) 2/18 b) 5/18 c) 4/9 d) 2/9

Answer:b) 5/18

Solution:

In a simultaneous throw of two dice, we have n(s) = 6 x 6 = 36
Let E = event of getting two numberswhose sum is at most 5.
Then E = { (1,1), (1,2), (1,3), (1,4), (2,1), (2,2), (2,3), (3,1), (3,2), (4,1)}
therefore, n(E) = 10
And P(E) = p( getting two numbers whose sum is at most 5)
P(E) = n(E)/n(s) = 10/36 = 5/18

Hence the answer is 5/18


Question 4
Two dice are thrown simultaneously. What is the probability of getting the face numbers are same?
a) 1/6 b) 2/3 c) 4/9 d) 5/6

Answer:a)1/6

Solution:

In a simultaneous throw of two dice, we have n(s) = 6x6 = 36
Let E = event of getting two numbers are same.
Then E = { (1,1), (2,2), (3,3), (4,4), (5,5), (6,6)}
therefore, n(E) = 6
And P(E) = p( getting two numbers are same)
P(E) = n(E)/n(s) = 6/36 = 1/6

Hence the answer is 1/6


Probability Problems Solved Questions (Page 2 of 4)

Score Well In SBI & IBPS, PO & Clerk Exams

Related pages


sbi.cmsbi marketing questionsidbi openingsirda questionssbi ibpsrbi question paperaryavart gramin bankvysya bank careersup sarva gramin bankfraction problem solving questionspnr formulasyllogisms questionswho is the head of rbi at presentbank po exam preparation booksbodmas questionsbi bank clericalgrama bankdeep water ports in indialargest auditorium in indiakvb openingsibps bank exam forminternational airport list in indiaibps po reasoning questionsslr rate definitionrtgs upper limitlk jha governor rbiimportant airports in indiasyllogisms practiceantonyms for diatribeibps careerslogical reasoning question papersmensuration testmsf rate definitionsums on hcf and lcmsbi compound interest calculatorlogical aptitude questions and answersibps pocanara bank specialist officertypes of numbers venn diagramramu rajubanks under ibps powho is the governor of rbi at presentorder and bearer chequeimprove antonymsrrb ibpsmath question and answer for bank exampermutations and combinations practice problems and solutionsenglish synonyms for bank examsibps po quantitative aptitude questions with answerspermutation and combination questions and answersbooks for bank examssolve cube root problemsgk questions of computeraptitude questions on probabilitycareer sbi banksbi bank clerkssyllogisms questions and answersibps rrb.inmixtures and allegationsantonyms for divulgegovernor of rbi in indiahow to solve hcf and lcmibps rrb inlist of airport in tamilnadubank po exam questions and answerscomputer gk questionscredit card allahabad bankibps exam for clerkcomputer gk questions with answerswhat are the types of chequesibps rrb.inandhra pradesh grameena vikas bank recruitmentsmallest lake in india